x^2+18x-14=11x-8

Solution for x^2+18x-14=11x-8 equation:

x^2+18x-14=11x-8

We move all terms to the left:

x^2+18x-14-(11x-8)=0

We get rid of parentheses

x^2+18x-11x+8-14=0

We add all the numbers together, and all the variables

x^2+7x-6=0

a = 1; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·1·(-6)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{73}}{2*1}=\frac{-7-\sqrt{73}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{73}}{2*1}=\frac{-7+\sqrt{73}}{2}
$